求j**a代码：金融系统中，钱的大写。

packagecom.format;import j**a.text.decimalformat;public class moneyformat {
private static final string[]num={"零","壹","贰","叁","肆","伍","陆",
柒","捌","玖","点"};private static final string[]m={"拾","佰","仟","万","亿"};private static final string[]int={"0","1","2","3","4","5","6",
7","8","9","."};public static string parsemoney(double money){
decimalformat format=new decimalformat("#.#");string moneystring=format.format(money).replaceall(",","");string[]ss=moneystring.split("");int pointindex=moneystring.indexof('.');if(pointindex=-1)
pointindex=ss.length-1;stringbuffer **=new stringbuffer();for(string s:ss){
if!.equals(s)&!.equals(s)){
int n=10;if!.".equals(s))
n=integer.parseint(s);**.append(num[n]);}
}
int j=0;for(int k=pointindex;k>1;k-){
j+;if(j){
**.insert(pointindex-j,m[j-1]);} else if(j){
**.insert(pointindex-j,m[j%4-1]);} else if(j=8){
**.insert(pointindex-j,m[j-4]);} else if(j){
**.insert(pointindex-j,m[j%8-1]);} else if(j){
**.insert(pointindex-j,m[j%12-1]);} else {
**=new stringbuffer();**.append("超出范围");}
}
return **.tostring();}
public static double parse(string money){
string moneystring=money;for(string m:m){
moneystring=moneystring.replaceall(m,"");}
stringbuffer **=new stringbuffer();for(string s:num){
**.append(s);}
string daxiestring=**.tostring();**=new stringbuffer();string[]ss=moneystring.split("");for(string s:ss){
int index=daxiestring.indexof(s);**.append(int[index]);}
return double.parsedouble(**.tostring());}
}
刚写出来的，给点分吧 展开