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2024-06-04 02:33:11
最佳回答
var1:=c-ref(c,1);var2:=100*ema(ema(var1,6),6)/ema(ema(abs(var1),6),6);ma5:=ema(c,5);ma13:=ema(c,13);up:=drawline(l=llv(l,barslast(cross(ma13,ma5))+1),llv(l,barslast(cross(ma13,ma5))+1),h=hhv(h,barslast(cross(ma5,ma13))+1),hhv(h,barslast(cross(ma5,ma13))+1),0);down:=drawline(h=hhv(h,barslast(cross(ma5,ma13))+1),hhv(h,barslast(cross(ma5,ma13))+1),l=llv(l,barslast(cross(ma13,ma5))+1),llv(l,barslast(cross(ma13,ma5))+1),0);hr:=hhv(high,55);hry:=llv(low,55);hry11:=hr*hry;hry33:=sqrt(hry11);短牛:=(llv(var2,2)=llv(var2,7) and count(var2<0,2) and cross(var2,ma(var2,2))) andref(down,1)<ref(down,2) and up>ref(down,1);中牛:=ref(down,1)<ref(down,2) and up>ref(down,1) and c<hhv(h,21)*0.82;大牛:=ref(down,1)<ref(down,2) and up>ref(down,1) and c<hry33;选三牛之一:短牛+中牛+大牛>0; 20210311