相关系数怎么算?????
楼上几位的回答可以说是误人子弟。x,y,x^2,y^2,xy990,400,980100,160000,3960001100,500,1210000,250000,550000∑2090,900,2190100,410000,946000相关系数r=(n∑xy-∑x∑y)/〔根号(n∑x^2-(∑x)^2)*根号(n∑y^2-(∑y)^2)〕=(2*946000-2090*900)/[根号(2*2190100-2090^2)*根号(2*410000-900^2)]=11000/(110*100)=1 20210311