Adorable
2024-05-22 16:56:48
最佳回答
tr:=expmema(max(max(high-low,abs(high-ref(close,1))),abs(ref(close,1)-low)),n);hd :=high-ref(high,1);ld :=ref(low,1)-low;dmp:=expmema(if(hd>0&&hd>ld,hd,0),n);dmm:=expmema(if(ld>0&&ld>hd,ld,0),n);pdi:= dmp*100/tr;mdi:= dmm*100/tr;a7:=c-ref(c,1);a8:=100*ema(ema(a7,6),6)/ema(ema(abs(a7),6),6);short:=7; long:=19;rma:=ema(close,short);nma:=ema(close,long);up:=drawline(l=llv(l,barslast(cross(nma,rma))+1),llv(l,barslast(cross(nma,rma))+1),h=hhv(h,barslast(cross(rma,nma))+1),hhv(h,barslast(cross(rma,nma))+1),0);down:=drawline(h=hhv(h,barslast(cross(rma,nma))+1),hhv(h,barslast(cross(rma,nma))+1),l=llv(l,barslast(cross(nma,rma))+1),llv(l,barslast(cross(nma,rma))+1),0);买进:(llv(a8,2)=llv(a8,7) and count(a8<0,2) and cross(a8,ma(a8,2))) and ref(down,1)<ref(down,2) and up>ref(down,1);参数自已输吧,验证了一下,可行的。 做人要厚道,记得给分。 20210311