dif:=ema(close,12)-ema(close,26);dea:=ema(dif,9);a1:=dif>dea;a2:=ma(c,5)>ma(c,10);a3:=ma(v,5)>ma(v,10);xg:a1 and a2 and a3;亲 上来晚了 上一个已经回答了!有看到你问了,给你复制过来咯,给分哦! 20210311
{今日价过5日均价.今日量过5日均量.macd的dif向上.kd金叉.今日价在20日均线上的选股}xg:cross(c,ma(c,5)) and cross(v,ma(v,5)) and macd.dif>ref(macd.dif,1) and cross(kdj.j,kdj.d) and c>ma(c,20);
因为这几个条件一般不会同时满足,你的原意应该 是在一指定的天数n内达到这些条件。因此我在公式中给你加了一个参数n,你试试。 ma5:=ma(c,5);ma10:=ma(c,10);ma30:=ma(c,30);ma130:=ma(c,130);xg:count(cross(ma5,ma10),n)>0 and count(cross(ma5,ma30),n)>0 and count(c...
ma5:=ma(c,5);ma10:=ma(c,10);ma30:=ma(c,30);ma60:=ma(c,60);xg:cross(ma5,ma30) and cross(ma5,ma60) and cross(ma10,ma30) and cross(ma10,ma60) and ma60>ma30 and ma5>ma10 and ma10>ma30;
mv5:=ma(amount,5);mv10:=ma(amount,10);mv20:=ma(amount,20);mv30:=ma(amount,30);tj1:=mv5>mv10 and mv10>mv20 and mv20>mv30;tj2:=mv5>ref(mv5,1) and mv10>ref(mv10,1) and mv20>ref(mv20,1) ...