要的公下,通过的a5:=ma(c,5);a10:=ma(c,10);a20:=ma(c,20);aa:=max(max(a5,a10),a20);aaa:=min(min(a5,a10),a20);aaaa:=aa/aaa<1.1;bb:=count(aaaa,12)=12;zm:capital <5000000 and bb;
通信达均量线多头排列: mv1:=ma(v,5);mv2:=ma(v,10);mv3:=ma(v,20);mv4:=ma(v,30);xg:mv1>mv2 and mv2>mv3 and mv3>mv4;通信达成交金额线多头排列: mam1:=ma(amount,5);mam2:=ma(amount,10);mam3:=ma(amount,20);mam4:=ma(amount,...
{xggs-}m5:=ma(c,5);m10:=ma(c,10);m20:=ma(c,20);m40:=ma(c,40);m50:=ma(c,50);xg:cross(c,m50)&m50>m5 and m50>m10 and m50>m20 and m50>m40;通过tdx测试。{个人看法,仅供参考。}