f:=100*(c-ref(c,1))/ref(c,1);今小昨:=if(c(o,1)and f,1,0);s1:=今小昨;今小前:=if(c(o,2)and f,1,0);s2:=今小前;a3:=s1=0 and ref(s1,1)=1 and s2=0 and ref(s2,1)=1 and cross(zig(3,10),ref(zig(3,10),1));a0:=zig(3,6)>r...
count(ref(c,1)/ref(c,2)>1.07 and ref(c,1)/ref(o,1)>1.07,5)>=1 and every(ref(c,1)>ma(c,20),5)and ref((l,h),1)<>ref((c,o),1)and abs(ref(c,1)/ref(o,1)-1)...