t1:=ma(c,5)>ma(c,10) and ma(c,10)>ma(c,30) and ma(c,30)>ma(c,60) and ma(c,60>ma(c,120));t2:=count(c>ma(c,5),3)=3;t3:=count(((c/ref(c,1)-1)*100)>8,10)>0;t4:=c
第一个:f:=100*(c-ref(c,1))/ref(c,1); 今小昨:=if(c<ref(o,1) and f<0,1,0); s1:=今小昨; 今小前:=if(c<ref(o,2) and f<0,1,0); s2:=今小前; a3:=s1=0 and ref(s1,1)=1 and s2=0 and ref(s2,1)=1 and cross(zig(3,10) ...