n:=11;{可调} ma(c,20)>ma(c,60)and ma(c,60)>ma(c,120)and count(l>ma(c,20),n)=n and hhv(h,n)/ref(c,n)(h,n)/llv(l,n) and sum(dyna**(37),n);{设n为 11,选出10只} 图例:
您的描述可理解为:最20日振幅大10%,目前股价中,正向20靠拢。把这样的股票选出来。公式如下(我又细化了一下):ar1:=(hhv(h,20)-llv(l,20))*100/llv(l,20)>10;ar02:=(c,5)<((c,5),1);ar2:=count(ar02,5)=5;ar3:=count(l/(c,20)<1.002 and h>ma(c,20),3)&...
a1:=every(c>o or c>ref(c,1),4);a2:=(c-ref(c,4))/ref(c,4)*100;a3:=(hhv(h,4)-llv(l,4))/llv(l,4)*100;a4:=v=hhv(v,10);xg:ex**t(a1 and a2 and a3 and a4,10)and cross(c,ma(c,10));