{1.}f:=100*(c-ref(c,1))/ref(c,1); 今小昨:=if(c<ref(o,1) and f<0,1,0); s1:=今小昨; 今小前:=if(c<ref(o,2) and f<0,1,0),linethick0; s2:=今小前; a3:=s1=0 and ref(s1,1)=1 and s2=0 and ref(s2,1)=1 and cross(zig(3,10) ,ref(zig(3 ,10),1));全仓:=drawtext(a3=1,3.8,'☆全仓杀入');智勇出击:=zig(3,6)>ref(zig(3,6),1)and ref(zig(3,6),1)<ref(zig(3,6),2);突袭:=智勇出击=1,0.8; xg: 突袭;{2.}f:=100*(c-ref(c,1))/ref(c,1); 今小昨:=if(c<ref(o,1) and f<0,1,0); s1:=今小昨; 今小前:=if(c<ref(o,2) and f<0,1,0),linethick0; s2:=今小前; a3:=s1=0 and ref(s1,1)=1 and s2=0 and ref(s2,1)=1 and cross(zig(3,10) ,ref(zig(3 ,10),1));全仓:=drawtext(a3=1,3.8,'☆全仓杀入');xg:全仓;公式含有未来函数。{个人看法,仅供参考。} 20210311
aobv:="obv.obv;amacd:="macd.macd;adif:="macd.dif;adea:="macd.dea;aa1:=h=hhv(aobv,120);aa2:=amacd>0 and adif>adea;aa3:=ma(c,5)>ma(c,10)>ma(c,20) 条件成立:aa1 and aa2 and aa3;